Today we are providing you “Quant – Permutation, Combination & Probability Day 24” in this post you will take section wise free mock test to boost up your IBPS PO Exam Preparation. Please share it with your friends.
Quant – Permutation, Combination & Probability Day 24
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Mission IBPS PO 2017 – Daily Free Mock Test
Quant Section : Permutation, Combination & Probability Day 24
No Of Question: 10
Test Time: 10 Mins
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Question 1 of 10
1. Question
In how many different ways can the letters of the word “CHARGES” be arranged in such a way that the vowels always come together?
Correct
A. 1440
6! ×2!=1440
Incorrect
A. 1440
6! ×2!=1440

Question 2 of 10
2. Question
In how many different ways can the letters of the word “COMPLAINT” be arranged in such a way that the vowels occupy only the odd positions?
Correct
B. 43200
– × – × – × – × –
2 vowels can be filled in 5 odd places in 5C_{3} ways.
Total ways= 5C_{3} × 3! × 6! = 43200
Incorrect
B. 43200
– × – × – × – × –
2 vowels can be filled in 5 odd places in 5C_{3} ways.
Total ways= 5C_{3} × 3! × 6! = 43200

Question 3 of 10
3. Question
In how many different ways can the letters of the word “CANDIDATE” be arranged in such a way that the vowels always come together?
Correct
A. 4320
6! × 4! / 2! × 2! = 4320
Incorrect
A. 4320
6! × 4! / 2! × 2! = 4320

Question 4 of 10
4. Question
In how many different ways can the letters of the word “RADIUS” be arranged in such a way that the vowels occupy only the odd positions?
Correct
D. 36
– × – × –
Total ways = 3! × 3! = 36
Incorrect
D. 36
– × – × –
Total ways = 3! × 3! = 36

Question 5 of 10
5. Question
In how many different ways can the letters of the word ‘LEADING’ be arranged in such a way that the vowels always come together?
Correct
C. 720
5! × 3! = 720
Incorrect
C. 720
5! × 3! = 720

Question 6 of 10
6. Question
In how many different ways can the letters of the word ‘CORPORATION’ be arranged so that the vowels always come together?

Question 7 of 10
7. Question
Out of 7 consonants and 4 vowels, how many words of 3 consonants and 2 vowels can be formed?
Correct
C. 25200
7C_{3 × }4C_{2 }× 5! = 25200
Incorrect
C. 25200
7C_{3 × }4C_{2 }× 5! = 25200

Question 8 of 10
8. Question
In how many ways can the letters of the word ‘LEADER’ be arranged?
Correct
C. 360
6! / 2! = 360
Incorrect
C. 360
6! / 2! = 360

Question 9 of 10
9. Question
In how many different ways can the letters of the word ‘SERVING’ be arranged?
Correct
A. 5040
Since no letter is used more than once.
hence total ways = ^{7}p_{7 }= 7! = 5040
Incorrect
A. 5040
Since no letter is used more than once.
hence total ways = ^{7}p_{7 }= 7! = 5040

Question 10 of 10
10. Question
In how many different ways can any 4 letters of the word ‘WORKING’ be arranged?
Correct
B. 840
Since all letters are unique, choosing any four letters will lead us to 7×6×5×4 = 840 permutations.
Incorrect
B. 840
Since all letters are unique, choosing any four letters will lead us to 7×6×5×4 = 840 permutations.
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